Speed of a car and a bus is 25 km/h and 15 km/h, respectively. If the time taken by the car to cover a distance of ‘8x’ km is 1 hour less than time taken by the bus to cover a distance of ‘6x’ km, then find the value of ‘8x’.
According to the question, (6x/15) – (8x/25) = 1 Or, (6x × 5 – 8x × 3) ÷ 75 = 1 Or, (30x – 24x) ÷ 75 = 1 So, x = 12.5 Required value = 8 × 12.5 = 100
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