Question
A train was initially moving at 60 km/hr, then increased
its speed by 15 km/hr after ‘z’ hours and continued for (z + 8) hours more. If the distance covered in the last (z + 8) hours is 900 km, find the distance covered in the first ‘z’ hours.Solution
ATQ, (60 + 15) × (z + 8) = 900 Or, 75 × (z + 8) = 900 Or, z + 8 = 12 Or, z = 4 Therefore, required distance traveled = 60 × 4 = 240 km
More Time and distance Questions
[{70 + (40 - 22) ÷ 3} ÷ 4] = ?
? % of 1200 = 20% of 30% of 3600
√ (96 + 1000 + 3000) = ?
Solve the following:
1500 ÷ (9 × 18 ÷ 6 × 3 – 45) ²
(7/5) × (3/4) × (5/9) × (6/7) × 3112 = ?
What will come in the place of question mark (?) in the given expression?
(125 × 64) ÷ (8 × 5) + (12.5)² – (144 ÷ 3) = ?
...?2 - (40% of 240) = 25 X 5
5.5 × 3.2 × 2.3 = ?
- Find the simplified value of the given expression.
(-8) x {15 - (-4) x (-5)}
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