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Let, the distance between point A to point B was ‘x’ km. So, x/50 – x/62 = 1.2 (31x – 25x)/1550 = 1.2 6x = 1860 x = 310 km Therefore, the time taken by Rohan to reach point B = 310/62 = 5 hours
16% of 250 + 32% of 500 = ?
{5% of (20 × 25) + 6% of (30 ×35)} ÷ 11 = ?
Find the value of 5342.5 +543.45+54.345 +5.4345+0.54345.
181/8 + 51/4 – 63/8 = ? + 9/2
5.45% of 1854 – 37.5% of 1096 = ? – 48% of 630
12% of 10% of 15% of 5000 + (12 x 15) = ?
If 32x + 1– 3x= 3x + 3– 32, then values of x are:
√3598 × √(230 ) ÷ √102= ?
If 840 ÷ 12 + 1025 ÷ 25 - n + 45 × 4 = 960 ÷ 16 × 132 ÷ 44, then the value of n is:
The sum of two numbers is 16 and their product is 63. The sum of their reciprocal is equal to: