Question
A school bus arrives at the school on time when it
maintains an average speed of 50 km/h. However, if the bus travels at an average speed of 40 km/h, it arrives 18 minutes late. Determine the total distance covered by the bus.Solution
Let the distance travelled by bus be 'D' km and usual time taken by bus to reach school be 'T' hours. So, 'D' = 50T -------- (I) And, 'D' = 40 x [T + (18/60) ] Or, 'D' = 40T + 12 -------- (II) From equation I and II, we get, 50T = 40T + 12 Or, 10T = 12 So, 'T' = (12/10) = 1.2 Therefore, required distance = 50T = 50 x 1.2 = 60 km
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