Question
Two cars, ‘X’ and ‘Y’, started from town ‘M’
and ‘N’ respectively towards each other at the same time. When they crossed paths after 6 hours, car ‘Y’ had covered 90 km more than car ‘X’. What distance did car ‘X’ cover in 4 hours if the total distance between the towns is 510 km?Solution
ATQ,
Let distance travelled by car ‘X’ at the time of meeting = ‘x’ km
So, distance travelled by car ‘Y’ at the time of meeting = ‘x + 90’ km
According to question;
x + x + 90 = 510
Or, 2x = 420
Or, x = 210
Distance travelled by car ‘X’ in 6 hours = 210 km
Speed of car ‘X’ = 210 / 6 = 35 km/h
Distance travelled by car ‘X’ in 4 hours = 35 × 4 = 140 km
A) Maverick
B) Paucity
C) Ostensible
D) Unfeigned
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