Question
Two bikers, ‘C’ and ‘D’, start from point ‘R’
and ‘S’ respectively towards each other. They meet after 7 hours, and biker ‘D’ has travelled 105 km more than biker ‘C’. What distance did biker ‘C’ travel in 3 hours, if the total distance between R and S is 595 km?Solution
ATQ,
Let distance travelled by biker ‘C’ = ‘x’ km
Then, distance travelled by biker ‘D’ = ‘x + 105’ km
According to question;
x + x + 105 = 595
Or, 2x = 490
Or, x = 245
Distance travelled by biker ‘C’ in 7 hours = 245 km
Speed of biker ‘C’ = 245 / 7 = 35 km/h
Distance travelled by biker ‘C’ in 3 hours = 35 × 3 = 105 km
More Time and distance Questions
Find the value of (x + y)² - (x - y)², where x = 15 and y = 7.
20% of 240 + 18% of 200 = ?
Find the Value of
[(82 × 162)/12] - 28 = ?
- Find the simplified value of the expression:
81 ÷ 9 of 3 × 4 + [12 of 5 – {18 of 2 × (10/5) ÷ 36}] – 15 36.76 + 2894.713 + 34965.11 =?
(30% of 400 - 20% of 540 + 35% of 1000) = ?
Simplify the following expression:
84 - [21 - {14 - (25 - 16 + 8) }] ÷ 3 X 6
32% of 450 + 60% of 150 = ? × 9
- What will come in the place of question mark (?) in the given expression?
(198/13) X (52/11) - ? ÷ 5 = 13 + 68 ÷ 4
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