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Speed = Distance/time = 400/25 = 16 km/hr According to the question, New time = 3/5 x 25 = 15 hrs New distance = 1/2 x 400 = 200 km Required speed = Distance left/Time left = 200/10 = 20 km/hr
l). p² - 29p + 204 = 0
ll). q² + 4q - 221 = 0
I. 20y² - 13y + 2 = 0
II. 6x² - 25x + 14 = 0
I. 27x² + 120x + 77 = 0
II. 56y² + 117y + 36 = 0
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
I). p2 = 81
II). q2 - 9q + 14 = 0
If x2 - 3x - 18 = 0 and y2 + 9y + 18 = 0, which of the following is true?
I. x2 + x – 42 = 0
II. y2 + 6y – 27 = 0
What is the nature of the roots of the quadratic equation x² – 5x + 7 = 0 ?
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 24x + 143 = 0
Equation 2: y² - 26y + 165 = 0