Question
Bus X left Delhi for Jaipur at 4:00 am and Bus Y left
Jaipur for Delhi at 6:00 am, while at 8:00 am the distance between both buses X and Y is (3T+2) km. If both buses crossed each other at 8:04 am and speed of bus Y is ((D/2)-280) km/hr more than that of bus X, then find total distance (in km) between Delhi and Jaipur.Solution
ATQ, Let speed of bus X be a km/hr. So, speed of bus Y = (a+600/2-280) = (a+20) km/hr. Distance covered by bus X and Y together in one hour = ((3×6+2))/4×60 = 300 km ATQ, a+a+20=300 a=140 Total distance between Delhi and Jaipur = a×4+(a+20)×2+20 = (6a+60) = 900 = 1.5D
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