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    Question

    Bus X left Delhi for Jaipur at 4:00 am and Bus Y left

    Jaipur for Delhi at 6:00 am, while at 8:00 am the distance between both buses X and Y is (3T+2) km. If both buses crossed each other at 8:04 am and speed of bus Y is ((D/2)-280) km/hr more than that of bus X, then find total distance (in km) between Delhi and Jaipur.
    A 2D Correct Answer Incorrect Answer
    B D Correct Answer Incorrect Answer
    C D/2 Correct Answer Incorrect Answer
    D Cannot be determined. Correct Answer Incorrect Answer
    E 1.5D Correct Answer Incorrect Answer

    Solution

    ATQ, Let speed of bus X be a km/hr. So, speed of bus Y = (a+600/2-280) = (a+20) km/hr. Distance covered by bus X and Y together in one hour = ((3×6+2))/4×60 = 300 km ATQ, a+a+20=300  a=140  Total distance between Delhi and Jaipur = a×4+(a+20)×2+20 = (6a+60) = 900 = 1.5D

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