Question
If a person walks 25% more than of his usual speed,
reaches his distance 90 minutes before. If the destination is 495 km away, then the usual speed of a person is (in km/hr)?Solution
Let the usual speed be x km/hr New speed = 125% of x = 5x/4 km/hr Distance = 495 km According to the question 495/x – 495/(5x/4) = 90/60 495 x [(5 – 4)/5x] = 3/2 Therefore, x = 495 x (1/5) x (2/3) = 66 km/hr
Which of the following statements regarding IPO listing gains is correct?
Mission Amrit Sarovar is aimed at developing and rejuvenating _______ water bodies in each district of the country during this Amrit Varsh, 75th Years ...
If the expected return on the market is 18% and the expected return on a stock with a beta of 1.2 is 20%, what is the risk-free rate?
Which financial ratio is used to assess a company’s ability to cover its short-term liabilities using only its most liquid assets?
Under the simplified procedure for working capital finance to Micro and Small Enterprises (MSEs) with working capital limits of up to Rupees five crore,...
Under SARFAESI Act, which type of asset can a bank seize without court intervention?
The term “leverage” in financial management typically refers to:
In derivatives market, individual/firm that take short and long positions in the same or different contracts at the same time to create a position which...
Which is the 1st operational bank of GIFT City?
Which of the following is not a type of Market risk ?
