Question
If a person walks 25% more than of his usual speed,
reaches his distance 90 minutes before. If the destination is 435 km away, then the usual speed of a person is (in km/hr)?Solution
Let the usual speed be x km/hr New speed = 125% of x = 5x/4 km/hr Distance = 435 km According to the question 435/x – 435/(5x/4) = 90/60 435 x [(5 – 4)/5x] = 3/2 Therefore, x = 435 x (1/5) x (2/3) = 58 km/hr
More Time and distance Questions
(√845 ×19.932+ √4230 ×14.385)/(√1765 ×4.877 ) = ?
{(√2305) % of 74.69} × 15.21 - 27.89 × 44.88 + 45.12% of 2399.87
The greatest number that will divide 398,436, and 542 leaving 7, 11, and 15 as remainders, respectively, is:
2470.03 ÷ 64.98 x 39.9 = ? + 20.32
(1709.87 ÷ 38.09) + (768.11 ÷ 23.87) + (6599.81 ÷ 88.06) = ?
25.02% of 460.02+?% of 300.02=295.21
What is the area (in cm²) of a square inscribed in a circle with a radius of 10√2 cm?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
65.22 of 359.98% + 459.99 ÷ 23.18 = ?
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