Question
If a person walks 20% more than of his usual speed,
reaches his distance 90 minutes before. If the destination is 459 km away, then the usual speed of a person is (in km/hr)?Solution
Let the usual speed be x km/hr New speed = 120% of x = 6x/5 km/hr Distance = 459 km According to the question 459/x – 459/(6x/5) = 90/60 459 x [(6 – 5)/6x] = 3/2 Therefore, x = 459 x (1/6) x (2/3) = 51 km/hr
When implementing Huffman Coding, a common issue arises if the generated codes are not unique prefixes (i.e., one code is a prefix of another, leading t...
Linux uses a time-sharing algorithm ___________
- Does Dijkstra's algorithm work for graphs with both negative and positive edge weights?
Which of the following best describes the relationship between Distributed Parallel Computing and Cloud Computing?Â
Mutex locks can be used in CPU scheduling.
Which of the following statements accurately describes the purpose of unit testing in software development?
What is the primary purpose of a system call?
When debugging an N-Queens problem solution using backtracking, a common issue is that the algorithm either finds no solutions or finds too many, includ...
A data analysis application needs to quickly find the minimum or maximum value in a dynamically changing dataset. While a min/max heap could be used, ho...
Which cloud deployment model is suitable for government organizations with strict regulations?
Relevant for Exams:
