Question
A woman walks to the market at (4/6) of her normal speed
and reaches 30 minutes late. Find her usual time to reach the market.Solution
(Simplify (4/6) to (2/3) first. We’ll use 2/3.)
ATQ, When distance is constant, Time ∝ (1 / Speed) So, the ratio of usual time to new time = 2 : 3 Let the usual time = 2t minutes and the new time = 3t minutes. 3t – 2t = 30 ⇒ t = 30 Usual time = 2t = 2 × 30 = 60 minutes
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