Question
A bike travels 96 km in 72 minutes. If the speed is
reduced by 12 km/h, find the time taken to cover the same distance.Solution
ATQ, Speed of the bike = (96/72) × 60 = 80 km/h New speed of the bike = 80 – 12 = 68 km/h So, required time = (96/68) × 60 = 84.7 minutes or about 1 hour and 25 minutes
cot 13˚
cot 14˚ ...If sin θ + cos θ = 1.2, find the value of sin θ. cos θ.
If tan A = 1, then what will be the value of sec² A + cosec² A?
2 × Tan 30° / (1 + Tan2 30°) equals:
- If sin (4A − B) = (√2/2) and cos (A + B) = (√2/2), where 0° < A, B < 90°, then find the value of ‘A’.
Find the Value of Sin⁶`Theta` + Cos⁶`Theta` + 3Sin² `theta` Cos²`Theta`
If sin(3θ) = cos(2θ), then find the value of θ between 0 and 90 degrees.
cos (sec-1 x) is equal to –
Find the value of sin 240 °