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Let the HCF of two numbers = y Let the two numbers be 3y and 5y. => 3y × 5y = 120 × y ⇒ 15y = 120y ⇒ 15y = 120 ⇒ y = 8 3y = 3 × 8 = 24 5y = 5 × 8 = 40 ∴ The two numbers are 24, 40.
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