Question
Rs. 2,400 is distributed among 'X', 'Y', and 'Z' in the
ratio 6:7:5, respectively. Find the difference between the amount received by 'X' and 'Y' together and 'Y' and 'Z' together.Solution
ATQ,
Let the amount received by 'X', 'Y', and 'Z' be Rs. 6x, Rs. 7x, and Rs. 5x, respectively. Amount received by 'X' and 'Y' = 2400 × (6x + 7x) / (6x + 7x + 5x) = Rs. 1800 Amount received by 'Y' and 'Z' = 2400 × (7x + 5x) / (6x + 7x + 5x) = Rs. 1600 Required difference = 1800 - 1600 = Rs. 200
? = 80% of 30% of (50 × 150) + 400
Simplify the following expression:
(164-1)/17×15× (28+1)
- Find the value of:
35% of [150% of (45 + 15) + 150] ÷ 75 × 80 540240 ÷ 24 ÷ 25 =?

7.4 × 8.2 + 3.5 × 4.5 = ? + 11.5 × 2.5
2 X 25 + (30% of 80) ÷ (10% of 120) = ?
15% of ? = 30% of 320 + 17 ×√676 – 63.5 × 8
5760 ÷ 45 × 15 = ?
15 × 35 ÷7 + 60% of 300 =?