Question
The ratio of the present ages of βAβ and βBβ is
11:9, respectively. After 5 years, the ratio of their ages will become 12:10. The sum of the present ages of βAβ and βBβ is:Solution
Let the present ages of βAβ and βBβ be β11xβ and β9xβ years, respectively ATQ; (11x + 5)/(9x + 5) = 12/10 Or, 110x + 50 = 108x + 60 Or, 2x = 10 Or, x = 5 Now, sum of present ages of βAβ and βBβ = 11 Γ 5 + 9 Γ 5 = 100
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