Question
The cost of a piece of diamond varies with the square of
its weight. A diamond of Rs.6,084 value is cut into 3 pieces whose weights are in the ratio 3: 2: 1. Find the loss involved in the cutting. type-sscSolution
Let cost = k(weight)² so, 6084 = k (3+2+1)² 6084 = k×36 k = 6084/36 = 159-----(1) so now the new cost - C= C1 + C2 + C3 =K(w₁)²+k(w₂)²+k(w₃)² =k (9+4+1) =159×14=2366 loss =6084-2366=3718
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