Question
If the mean proportion of 1.44 and 2.25 is 'k', then find
the value of '3k'.Solution
k = √(1.44 × 2.25) = √3.24 = 1.8
Required value = 3 × 1.8 = 5.4
I. 3x2 - 14x + 15 = 0
II. 15y2 - 34 y + 15 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
Equation 1: x² - 144x + 5184 = 0
Equation 2: y² - 130y + 4225 = 0
Let 's' represent the sum of the highest root of equations I and III, and 'r' denote the product of the lowest root of equation I and the highest root o...
I. p2 – 15p + 56 = 0
II. q2 + 2q – 63 = 0
I. 2y2 - 15y + 18 = 0
II. 2x2 + 9x - 18 = 0
I. x2 + (9x/2) + (7/2) = - (3/2)
II. y2 + 16y + 63 = 0
I. 165x² + 97x + 10 = 0
II. 117y² - 163y + 56 = 0
- Suppose both the roots of q² + kq + 49 = 0 are real and equal, then determine the value of 'k'.
I.√(3x-17)+ x=15
II. y+ 135/y=24