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    Question

    Mahika distributed 800 chocolates among A, B and C. A

    got 50% more chocolates than B and 60% less chocolates than C. How many chocolates did C receive?
    A 480 Correct Answer Incorrect Answer
    B 300 Correct Answer Incorrect Answer
    C 400 Correct Answer Incorrect Answer
    D 320 Correct Answer Incorrect Answer
    E 240 Correct Answer Incorrect Answer

    Solution

    Total chocolates = A + B + C = 800
    A = (100 + 50)% of B
    B = 2A/3
    And A = (100 - 60)% of C
    C = 5A/2
    Now, A + 2A/3 + 5A/2 = 800
    A = 192
    Therefore, number of chocolates received by C = 5A/2 = 192 * 5/2 = 480

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