Question
Mahika distributed 800 chocolates among A, B and C. A
got 50% more chocolates than B and 60% less chocolates than C. How many chocolates did C receive?Solution
Total chocolates = A + B + C = 800
A = (100 + 50)% of B
B = 2A/3
And A = (100 - 60)% of C
C = 5A/2
Now, A + 2A/3 + 5A/2 = 800
A = 192
Therefore, number of chocolates received by C = 5A/2 = 192 * 5/2 = 480
I. 2y2 – 19y + 35 = 0
II. 4x2 – 16x + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 42x + 392 = 0
Equation 2: y² - 46y + 480 = 0
Equation 1: x² - 120x + 3500 = 0
Equation 2: y² - 110y + 3025 = 0
Find the coefficient of x³ in (2x − 3)⁶.
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 22x + 120 = 0
Equation 2: y² - 25y + 144 = 0
Find the value of 'x' and 'y' in the following equation:
7x - 2y = 46
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x² - 8x + 15 = 0 ...
l. 3x2 + 17x + 24 = 0
II. 2y2 + 15y + 27 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y.
I. x
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
