Question
Mahika distributed 800 chocolates among A, B and C. A
got 50% more chocolates than B and 60% less chocolates than C. How many chocolates did C receive?Solution
Total chocolates = A + B + C = 800
A = (100 + 50)% of B
B = 2A/3
And A = (100 - 60)% of C
C = 5A/2
Now, A + 2A/3 + 5A/2 = 800
A = 192
Therefore, number of chocolates received by C = 5A/2 = 192 * 5/2 = 480
What will be the median of the given data?
1, 1.1, 2.3, 0.1, 0.9, 5, 3.9, 2.5, 4.2, 4.6
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