Question
Mahika distributed 800 chocolates among A, B and C. A
got 50% more chocolates than B and 60% less chocolates than C. How many chocolates did C receive?Solution
Total chocolates = A + B + C = 800
A = (100 + 50)% of B
B = 2A/3
And A = (100 - 60)% of C
C = 5A/2
Now, A + 2A/3 + 5A/2 = 800
A = 192
Therefore, number of chocolates received by C = 5A/2 = 192 * 5/2 = 480
More Ratio and proportion Questions
32 X 25 ÷ 4 + 12 of 30 = ? X 5 - 30Â
Evaluate: 18 ÷ 3 × 4 + 6 − 5
25% of 250 + 32% of 200 = ? ÷ √ 16
15% of 1800 + 22 = ?Â
118 × 6 + 13 + 83 = ?
- What will come in the place of question mark (?) in the given expression?
35% of 400 - 20% of 300 = (? - 30) X 2 - What will come in place of the question mark (?) in the following questions?
120÷(5×2)+8=? √? = 32% of 900 + 48% of 50
 Â
