Question
The ratio of two numbers βAβ and βBβ is 3:5,
respectively. If 10 is added to each of βAβ and βBβ, then the ratio of βAβ and βBβ becomes 5:7. The sum of βAβ and βBβ is:Solution
Let the two numbers βAβ and βBβ be β3xβ and β5xβ, respectively ATQ; (3x + 10)/(5x + 10) = 5/7 Or, 21x + 70 = 25x + 50 Or, 4x = 20 Or, x = 5 Now, sum of βAβ and βBβ = 3 Γ 5 + 5 Γ 5 = 40
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