Question
Three numbers ‘P’, ‘Q’ and ‘R’ are such
that ‘P’ is one-third of ‘Q’ and ‘R’ is equal to the average of ‘P’ and ‘Q’. If the sum of these three numbers is 480, then find the value of the largest number.Solution
Let the value of ‘Q’ be ‘3x’ So, value of ‘P’ = 3x/3 = ‘x’ So, value of ‘R’ = (3x + x)/2 = 4x/2 = ‘2x’ ATQ; x + 3x + 2x = 480 Or, 6x = 480 Or, x = 80 So, the largest number = ‘Q’ = 3x = 3 × 80 = 240
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