Question
Three numbers βPβ, βQβ and βRβ are such
that βPβ is one-third of βQβ and βRβ is equal to the average of βPβ and βQβ. If the sum of these three numbers is 480, then find the value of the largest number.Solution
Let the value of βQβ be β3xβ So, value of βPβ = 3x/3 = βxβ So, value of βRβ = (3x + x)/2 = 4x/2 = β2xβ ATQ; x + 3x + 2x = 480 Or, 6x = 480 Or, x = 80 So, the largest number = βQβ = 3x = 3 Γ 80 = 240
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