Question
Three numbers βPβ, βQβ and βRβ are such
that βPβ is one-third of βQβ and βRβ is equal to the average of βPβ and βQβ. If the sum of these three numbers is 480, then find the value of the largest number.Solution
Let the value of βQβ be β3xβ So, value of βPβ = 3x/3 = βxβ So, value of βRβ = (3x + x)/2 = 4x/2 = β2xβ ATQ; x + 3x + 2x = 480 Or, 6x = 480 Or, x = 80 So, the largest number = βQβ = 3x = 3 Γ 80 = 240
40 Γ 55.96 Γ· 7 β 20% of 699.81 + 63Β = ? - (11479.50 Γ· 7)
350 Γ· 5 + 30 % of 180 + ? * 12 = 48 * β16
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
[(2/3 of 899.79) + 25% of 500.21] Γ (β195.77 + 30.03% of 399.79) = ?
? = 28.04Β² Γ· (4.01β΅ + 9.89 Γ 20.20) + 84.56% of (198.76 Γ 30.03)
(80.95) (1/4) + (3.05) 3 - 119.78 Γ 2.15 + (14.98)2 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)