Question
In the given figure, a circle is inscribed in Δ PQR,
such that it touches the sides PQ, QR and RP at points D, E, F, respectively. If the lengths of the sides PQ = 15 cm, QR = 11 cm and RP = 13 cm, then find the length of PD.Solution
A circle is inscribed in Δ PQR, such that it touches the sides PQ, QR and RP at points D, E, F, respectively. ⇒ PD = PF = x         ⇒ QD = QE = y ⇒ RE = RF = z All are tangents. ⇒ PD + PF + QD + QE + RE + RF = PQ + QR + RP ⇒ x + x + y + y + z + z = 39 ⇒ 2x + 2(y + z) = 39 Here, y + z = QE + ER = RQ And we have RQ = 11 ⇒ 2x + 2(11) = 39 ⇒ 2x + 22 = 39 ⇒ 2x = 17 ⇒ x = 8.5 ⇒ PD = 8.5 cm
((9.77)0- 〖(0.1)〗(-1))/(〖(6/24 )〗(-1) ×(3/2)3+ 〖((-2)/6)〗(-1) ) = ?
...What will come in place of the question mark (?) in the following questions?
[{(3 × 54 × 21)/63} + 6] / 6 = √?Â
(24% of 500 - 20) ÷ 25 = ? ÷ 4
What will come in the place of question mark (?) in the given expression?
(18 × 8 ÷ 12) × 10 = ?
- What will come in place of (?), in the given expression.
(4² + 6²) × 2 = ? 16 × 14 + 30 × 21 = 14 × ?
1*1/2 + 11*1/3 + 111*1/2 + 1111*1/3 + 11111*1/3 =?
40 × 5 + 27) × 9 = ?
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