The cost of fencing a rectangular field at the rate of Rs. 5/metre is Rs. 330. If the length of the field is 11 metres more than its breadth, then find the length of the rectangular field.
Let the length of the rectangular field be ‘l’ m Breadth of the rectangular field = (l – 11) m Therefore, perimeter of the rectangular field = 2 ×(l + l – 11) = (4l – 22) m According to the question, 4l – 22 = 330/5 Or, 4l = 66 + 22 Or, l = 88/4 = 22 metres
Statements: Q % G & Z % G; G # C & E; E @ P # D
Conclusions : I. C @ P II. Q % P ...
Statements: S%R, R@U, U & V, V # N
Conclusions :
I. N @ U
II. R @ N
...
Statements: A ≥ B > C, N ≤ M ≤ D = C, X ≤ P ≤ O = N
Conclusion:
I. C ≥ P
II. P = N
Statements: A @ D % M % N; M $ P $ Q
Conclusions : I. D % Q I...
Statements: M ≤ N; O < R; O = N; S ≥ Q; N > S
Conclusions:
(i) Q < M
(ii) N ≥ Q
(iii) M > R
...Statements: Y $ Z, H $ D, Z * D
Conclusions: a) Y & H b) Y * D
...Which of the following will be definitely true if the given expression L > M ≥ N > O ≥ P > Q = S ≤ T > R ≤ U is definitely not true?
Statement: C < D ≤ E; F > E ≤ G ; D ≥ H
Conclusions: I. G = H II. G > H
...Statements : B ≤ I; E = D; H > F; C ≤ H; I = D; A ≤ B; H < E
Conclusions:
(i) I > F (ii) B ≤ H (iii) A ≤ E (iv) E ...
Statement: B = E ≥ F ≥ M < J < V ≥ R; M > A
Conclusion:
I. A ≥ R
II. B > A
...
