Question
Three numbers ‘A’, ‘B’ and ‘C’ are such
that ‘A’ is double of ‘B’ and ‘C’ is equal to the average of ‘A’ and ‘B’. If the sum of these three numbers is 630, then find the value of ‘C’.Solution
Let the value of ‘B’ be ‘2x’ So, value of ‘A’ = 2 × 2x = ‘4x’ So, value of ‘C’ = (4x + 2x)/2 = 6x/2 = ‘3x’ ATQ; 4x + 2x + 3x = 630 Or, 9x = 630 Or, x = 70 So, the value of ‘C’ = 3x = 3 × 70 = 210 Let the value of ‘B’ be ‘2x’ So, value of ‘A’ = 2 × 2x = ‘4x’ So, value of ‘C’ = (4x + 2x)/2 = 6x/2 = ‘3x’ ATQ; 4x + 2x + 3x = 630 Or, 9x = 630 Or, x = 70 So, the value of ‘C’ = 3x = 3 × 70 = 210
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