Question
Three numbers βAβ, βBβ and βCβ are such
that βAβ is double of βBβ and βCβ is equal to the average of βAβ and βBβ. If the sum of these three numbers is 630, then find the value of βCβ.Solution
Let the value of βBβ be β2xβ So, value of βAβ = 2 Γ 2x = β4xβ So, value of βCβ = (4x + 2x)/2 = 6x/2 = β3xβ ATQ; 4x + 2x + 3x = 630 Or, 9x = 630 Or, x = 70 So, the value of βCβ = 3x = 3 Γ 70 = 210 Let the value of βBβ be β2xβ So, value of βAβ = 2 Γ 2x = β4xβ So, value of βCβ = (4x + 2x)/2 = 6x/2 = β3xβ ATQ; 4x + 2x + 3x = 630 Or, 9x = 630 Or, x = 70 So, the value of βCβ = 3x = 3 Γ 70 = 210
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