Question
Two classmates R and S stand at points U and V
respectively. R starts toward V from U at a speed of (x – 5) km/h. After 3 hours, S starts toward U from V at a speed of (x + 5) km/h. They meet exactly at the midpoint of UV. If UV = 360 km, find the time taken by R to go from U to V.Solution
ATQ, Distance covered by R in 3 hours = (x – 5) × 3 = 3(x – 5) km Remaining distance between them = 360 – 3(x – 5) = 360 – 3x + 15 = (375 – 3x) km Time of meet after S starts = (375 – 3x)/(2x) hours According to question, [(375 – 3x)/(2x)] × (x + 5) = 360/2 (375x + 1875 – 3x² – 15x) = 360x ⇒ –3x² + 1875 = 0 3x² = 1875 x² = 625 x = 25 Speed of R = 25 – 5 = 20 km/h Therefore, required time = 360/20 = 18 hours
A, residing in Calcutta, is agent for Z, residing at Delhi. There is an express or implied contract between A and Z, that all sums remitted by Z to A sh...
According to the LIC Act, 1956, which fund does the Corporation maintain for carrying out its insurance business?
The directors of a company can borrow money exceeding paid up share capital and free reserves by ____________
The concept of Ombudsman first originated in:
What is the minimum amount of default specified by the Central Government for initiating insolvency and liquidation proceedings under IBC?
As provided under the Indian Constitution, Separation of Judiciary from Executive is a _________.
The Indian Evidence Act, 1872 came into force on
Under The Indian Contract Act, 1872, requisite for a valid ratification is.
Section 223(1) provisos provide that if a case is made over to another Magistrate under section 212, the new Magistrate—Â
Who can the High Court appoint to exercise jurisdiction in a Court of Session?
