Question
Two cyclists P and Q are at towns A and B. P sets off
toward B at (x – 8) km/h. Two hours later, Q starts toward A at (x + 8) km/h. They meet at the exact halfway point between A and B. If AB = 240 km, find P’s time to go from A to B.Solution
ATQ, Distance covered by P in 2 hours = (x – 8) × 2 = 2(x – 8) km Remaining distance = 240 – 2(x – 8) = 240 – 2x + 16 = (256 – 2x) km Time of meet after Q starts = (256 – 2x)/(2x) hours According to question, [(256 – 2x)/(2x)] × (x + 8) = 240/2 (256x + 2048 – 2x² – 16x) = 240x ⇒ –2x² + 2048 = 0 x² = 1024 x = 32 Speed of P = 32 – 8 = 24 km/h Therefore, required time = 240/24 = 10 hours
28(4/5) + 52(1/2) × 8(2/7) - 11(1/5) = ? + 6(1/5)
Find the value of 45 - 3 x (4 of 6 + 12 ÷ 3 × 6 – 4 × 5) + 6.
26 2 – 13% of 400 + (529 ÷ 23 2 ) = ? 2
Simplify the following expression:-
√10000 x √8100 - (50)² = √(?) + (80)²
(18% of 360) ÷ 0.4 = ?
3.55 + 1.05 + 2.5 × 13 – 12% of 12.5 = ?
? = 6.25% of 240 + 25 2 + 17 2 – 16 × 17
√256 * 4 – 30% of 190 + ? = 110% of 220
