Question
Two runners A and B stand at opposite ends M and N of a
straight track. A begins toward N at (x β 6) km/h. Four hours later, B starts toward M at (x + 6) km/h. They meet at the midpoint of MN. If MN = 576 km, determine how long A would take to cover the entire MN.Solution
ATQ, Distance covered by A in 4 hours = 4(x β 6) km Remaining distance = 576 β 4(x β 6) = 576 β 4x + 24 = (600 β 4x) km Time of meet after B starts = (600 β 4x)/(2x) hours According to question, [(600 β 4x)/(2x)] Γ (x + 6) = 576/2 (600x + 3600 β 4xΒ² β 24x) = 576x β β4xΒ² + 3600 = 0 xΒ² = 900 x = 30 Speed of A = 30 β 6 = 24 km/h Therefore, required time = 576/24 = 24 hours
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