Outer diameter of 20 cm long pipe is 25 cm. If the thickness of the metal in the pipe is 1 cm. Find the total surface area of the pipe?
Outer part surface area = 2(22/7)Rh Inner part surface area = 2(22/7)rh Area of shaded portion = 2 (22/7) R² - ((22/7) r)² = (22/7) (R² - r²) Total surface area = 2(22/7)Rh + 2(22/7)rh + 2(22/7) (R² - r²) = 2 (22/7) (R+r) [h + R - r] = 2 (22/7) (R+r) [h + thickness] Required surface area = 2× 22/7 (R+r) [h + thickness] = 2× 22/7× (12.5 + 11.5)× 21 = 132× 24 = 3168
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