Question
An electron and a proton are accelerated by the same
potential difference. Which one has a longer de Broglie wavelength?Solution
When an electron and a proton are accelerated through the same potential difference, they both gain the same kinetic energy (since K.E. = qV, and both have equal magnitude of charge). The de Broglie wavelength is given by: λ = h / √(2mK.E.) For equal kinetic energy:
- λ ∝ 1 / √m
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