Question
Find the fourth proportion of (2k), (3k), and (4k + 8).
(Note: 'k' is the smallest two-digit prime number.)Solution
k = 11
2k = 22
3k = 33
4k + 8 = 44 + 8 = 52
22 : 33 :: 52 : m
22m = 33 × 52 = 1716
m = 1716 ÷ 22 = 78
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