Question
40 liters of milk are kept in a container. 10 liters
were removed and replaced with water. This procedure was performed two more times. How much milk does the container now hold?Solution
we know that. remaining milk in the container = Original amount × [1- amount taken out /original amount] ⁿ = 40[1-10/40] ³ =40[3/4] ³ =40 × 27 /64 =16.8 liters
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A crossing of two or more breeds and alternately mating the hybrid females over several generations with males of the original breeds is called
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