Question
Marks scored by A and B in a test are in the ratio 15:7
respectively. If B had scored 10 more marks, then marks scored by A would be 25% more than that of B. Find the difference between actual marks scored by A and B.Solution
Let actual marks scored by A and B be 15x and 7x respectively. Difference between the marks scored by A and B = 15x – 7x = 8x According to question, => (7x + 10) × 1.25 = 15x => 8.75x + 12.5 = 15x => 6.25x = 12.5 => x = 2 Required difference = 8x = 16
Find the value of tan(75°) using the identity for tan(A+B).
If cos2B = sin(1.5B + 20o), then find the measure of 'B'.
The minimum value of 45 sin2 θ + 28 cos2 θ is
If √3cosec 2x = 2, then the value of x:
if 8 sin 2 x + 3 cos 2 x = 4  then find tan x
If cos 2A = 17, then find cos A
Find the value of: (Sin2 60 ° X cos 30 ° X sec 60°)/tan 30°
Simplify the following trigonometric expression:Â
15 cos 25° cosec 65° − 5 cot 80° cot 10°
If sin(3θ) = cos(2θ), then find the value of θ between 0 and 90 degrees.