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Average = (sum of observations)/(number of observations)
Let the number of elephants, tigers and lions in the zoo are E, T and L respectively.
Now, 78 = (E + T + L)/3
E + T + L = 234
(E + L)/2 = 71
E + L = 142
Then, T + 142 = 234
T = 92
Now, T = 6 + E
92 = 6 + E
E = 86
And L = 142 - L = 142 - 86 = 56
Therefore, the average number of tigers and lions in the zoo = (T + L)/2 = (92 + 56)/2 = 74
41.5% of ? + 64.69% of 419.1 = 504.2
(88.931% of 435) + (61.521% of 516) = ?
3.992 + (3.01 × 2.98) + ? = 225.03
80.08% of 1250.25 + 64.02% of 1200 = 24.02 × 36.025 + ?% of 2259.98
(27.08)2 – (14.89)2 – (22.17)2 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
? 3 + 95.06 X 39.87 ÷ 5.03 = 1271.89
17.98% of (16.93 X 8.992 + 46.87) = ? of 14.92 - 26.83 of 1.98
63.981 + 64.001 + 65.08019 + 63.11112 =?
?% of (150.31 ÷ 14.97 × 50.011) = 319.98