Question
Three numbers βAβ, βBβ and βCβ are such
that βAβ is 40% less than βBβ and βCβ is the average of βAβ and βBβ. If the sum of βAβ and βCβ is 350, then find the value of βBβ.Solution
Let the value of βBβ be β10xβ So, value of βAβ = 10x β {40% of 10x} = β6xβ So, value of βCβ = (6x + 10x)/2 = 16x/2 = β8xβ ATQ; 6x + 8x = 350 Or, 14x = 350 Or, x = 25 So, the value of βBβ = 10x = 10 Γ 25 = 250
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