Question
Three numbers βAβ, βBβ and βCβ are such that
βAβ is half of βBβ and βCβ is equal to average of βAβ and βBβ. If sum of these three numbers is 540, then ind the second highest number among the three.ΒSolution
Let the value of βBβ be β2xβ So, value of βAβ = 2x/2 = βxβ So, value of βCβ = (2x + x)/2 = 3x/2 = β1.5xβ ATQ; x + 1.5x + 2x = 540 Or, 4.5x = 540 Or, x = 120 So, the second highest number = βCβ = 1.5x = 1.5 Γ 120 = 180
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