Question
Find the fourth proportion of (3k + 3), (6k + 6) and
(9k + 9). (Note: 'k' is the largest single-digit composite number.)Solution
'k' = 9 3k + 3 = 3 Ă— 9 + 3 = 30 6k + 6 = 6 Ă— 9 + 6 = 60 9k + 9 = 9 Ă— 9 + 9 = 90 Let the fourth proportion be 'm'. 30 : 60 :: 90 : m So, 30 Ă— m = 60 Ă— 90 Or, 'm' = 180
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