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      Question

      A container holds 180 litres of a milk and water

      mixture, where the amount of milk exceeds the amount of water by 44 litres. If 8 litres of milk and 12 litres of water are added to this mixture, what will be the ratio of milk to water in the final solution?
      A 2:1 Correct Answer Incorrect Answer
      B 3:2 Correct Answer Incorrect Answer
      C 6:5 Correct Answer Incorrect Answer
      D 7:4 Correct Answer Incorrect Answer

      Solution

      Let the quantity of water in the 180-litre mixture = ‘y’ litres
      Quantity of milk in the 180-litre mixture = (y + 44) litres
      So, y + y + 44 = 180
      Or, y = (180 – 44) ÷ 2 = 68 litres
      So, original quantity of milk in the mixture = 68 + 44 = 112 litres
      So, required ratio = (112 + 8):(68 + 12)
      = 120:80 = 3:2

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