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Let the quantity of water in the 180-litre mixture = ‘y’ litres
Quantity of milk in the 180-litre mixture = (y + 44) litres
So, y + y + 44 = 180
Or, y = (180 – 44) ÷ 2 = 68 litres
So, original quantity of milk in the mixture = 68 + 44 = 112 litres
So, required ratio = (112 + 8):(68 + 12)
= 120:80 = 3:2
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