Question
The cost of diamond varies directly as the square of its
weight. A diamond broke into four pieces with weights in the ratio 1 : 3 : 4 : 7. if the loss in the total value of the diamond was Rs. 90,000. The price of the original diamond was?ĀSolution
Let the weight of the pieces of diamond be x, 3x, 4x, 7x Total weight of diamond = x + 3x + 4x + 7x = 15x Price ā (weight)2 => Price = k(weight)2 ; where, K is constant Original price = k(15x)2 Price of pieces = (kx2 + 9kx2 + 16kx2 + 49kx2) = 75kx2 Loss in price = 225kx2 ā 75kx2 = 150kx2 which is given as 90,000 => 150kx2 = 90000 => kx2 = 600 Original price = 225kx2 = 225 x 600 = 135000
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