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      Question

      Q and L have chocolates in the ratio of 7: 8 and B and N

      have chocolates in the ratio of 2: 5. Q has 20 more chocolates than B and sum of chocolates of B and N is 3 times of number of chocolates Q have, then what is the average number of chocolates Q, L, B and N have?
      A 120 Correct Answer Incorrect Answer
      B 140 Correct Answer Incorrect Answer
      C 160 Correct Answer Incorrect Answer
      D 150 Correct Answer Incorrect Answer
      E 180 Correct Answer Incorrect Answer

      Solution

      Let Q = 7x and L = 8x and B = 2y and N = 5y
      Given, Q = 20 + B
      => 7x - 2y = 20 ---(1)
      And (B + N) = 3Q
      => 2y + 5y = 3 * 7x
      => y = 3x ---(2)
      Putting value of y in equation (1), we get
      7x - 2 * 3x = 20
      => x = 20
      Thus, y = 60
      So, required average = (15x + 7y)/4 = (15 * 20 + 7 * 60)/4 = 180

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