Question
The ratio between two numbers is 4:5. If each number is
increased by 6, the ratio between then become 7:8, find the difference between numbers.Solution
Let first number be 4x and the second number is 5x. According to the question, => (4x + 6)/(5x + 6) = 7/8 => 32x + 48 = 35x + 42 => x = 2 Required difference = 5x – 4x = x = 2
The L.C.M of a² – 2a – 3 and a³ + a² + a + 1 isÂ
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