Question
Quantity-I: ‘A’ and ‘B’ started a business by
investing Rs.‘x’(Take 'x' value as approximate) and Rs. 5,500, respectively. ‘A’ and ‘B’ invested their sum for 10 months and 12 months, respectively. If ratio of profit share of ‘A’ and ‘B’ is 4:5, respectively, then find the value of ‘x’? Quantity-II: If a = 6:7 and b = 2100, then find the value of ‘a’. In the question, two Quantities I and II are given. You have to solve both the Quantity to establish the correct relation between Quantity-I and Quantity-II and choose the correct option.Solution
Quantity I: According to the question; {(x × 7)/(2500 × 11)} = 5/6 Or, x = 3285.71 (approx) So, Quantity I = 3285.71 Quantity II: a = (7/5) × 2250 = 3150 So, Quantity II = 3150 Therefore, Quantity I > Quantity II
The average of three numbers a, b and c is 2 more than c. The average of a and b is 48. If d is 10 less than c, then the average of c and d is:
If the sum of three numbers is zero, then which of the options below will always be equal to the value of the sum of the cubes of those numbers?
If  x = 19 , find x 5 - 20  x 4 + 20  x 3 - 20x 2 + 20x  - 20 = ?
Given that x8-34x4+1=0, x>0. What is the value of (x3+ x-3)?
If x2a = y2b =z2c ≠ 0 and x2 = yz, then the value of (ab + bc + ca) /bc is :
when x =4 and y =-6 then find the value of 27x³ +58x²y +31xy² +8y³?
Given that x = 80, y = -35 and z = -45, Determine the value of [(x³ + y³ + z³)/10³]
22% of ‘x’ is equal to 66% of ‘y’, then find the value of x: y.
If, 4x + y = 10, and 2xy = 8, and 4x > y, then find the value of 64x³ – y³.
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