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      Question

      How many litres of liquid A was contained by the Can

      initially? Quantity I. A Can contains a mixture of two liquids A and B in the ratio┬а7: 5. When 9 litres of mixture are drawn off and the Can is filled with B, the ratio of A and B becomes 7: 9 . Quantity II. A Can contains a mixture of two liquids A and B in the ratio┬а4:1. When 10 litres of mixture are drawn off and the Can is filled with B, the ratio of A and B becomes 2: 3 Study the following information carefully and answer the Questions given below:
      A Quantity I > Quantity II Correct Answer Incorrect Answer
      B Quantity I < Quantity II Correct Answer Incorrect Answer
      C Quantity I тЙе Quantity II Correct Answer Incorrect Answer
      D Quantity I тЙд Quantity II Correct Answer Incorrect Answer
      E Quantity I = Quantity II or No relation can be established Correct Answer Incorrect Answer

      Solution

      Quantity I. Suppose the Can initially contains 7x and 5x litres of mixtures A and B respectively.┬а Quantity of A in mixture left = (7x-7/12├Ч9) = (7x-21/4) litres Quantity of B in mixture left = (5x-5/12├Ч9) = (5x-15/4) litres ((7x-21/4))/((5x-15/4+9) ) = 7/9┬а тЗТ (28x тАУ 21 )/(20x + 21) = 7/9 тЗТ 252x тАУ 189 = 140x + 147 ┬а тЗТ x = 3. тИ┤ Quantity of A in the Can initially = 7 x = 21 Quantity II. Suppose the Can initially contains x and 4x litres of mixtures A and B respectively.┬а Quantity of A in mixture left = (4x-4/5├Ч10) = (4x-8) litres Quantity of B in mixture left = (1x-1/5├Ч10) = (1x-2) litres┬а ((4x-8))/((1x-2 +10) ┬а) = 2/3 ┬а тЗТ 12x тАУ 24 = 2x + 16 ┬атЗТ x = 4. тИ┤ Quantity of A in the Can initially = 4x = 16 Hence, Quantity I > Quantity II

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