Question
Pipes 'A', 'B', and 'C' working
together can fill a tank in 4 hours, while pipes 'B' and 'C' together can fill the same tank in 20/3 hours. How long would pipe 'A' take to fill 45% of the tank by itself?Solution
ATQ, Let the capacity of tank = 60 units (LCM of 4 and 20/3) Efficiency of 'A', 'B' and 'C' together = 60 ÷ 4 = 15 units per hour Efficiency of 'B' and 'C' together = 60 ÷ (20/3) = 60 X (3/20) = 9 units per hour So, Efficiency of 'A' = 15 − 9 = 6 units per hour Required time = (60 X 0.45) ÷ 6 = 4.5 hours = 4 hours 30 minutes
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