Question
Pipes 'A', 'B', and 'C' working
together can fill a tank in 4 hours, while pipes 'B' and 'C' together can fill the same tank in 20/3 hours. How long would pipe 'A' take to fill 45% of the tank by itself?Solution
ATQ, Let the capacity of tank = 60 units (LCM of 4 and 20/3) Efficiency of 'A', 'B' and 'C' together = 60 ÷ 4 = 15 units per hour Efficiency of 'B' and 'C' together = 60 ÷ (20/3) = 60 X (3/20) = 9 units per hour So, Efficiency of 'A' = 15 − 9 = 6 units per hour Required time = (60 X 0.45) ÷ 6 = 4.5 hours = 4 hours 30 minutes
√1764 + 35 × 8 + 39 = ?2
18% of 200 - 16% of 150 = ?
25% of 30% of 3/5 of 14500 =?
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
7/3 of 4/5 of 15/56 of ? = 83
What will come in place of the question mark (?) in the following expression?
40% of 150 – ?% of 80 = 25% of 400
555.05 + 55.50 + 5.55 + 5 +0.55 = ?
64.5% of 800 + 36.4% of 1500 = (?)² + 38
What will come in the place of question mark (?) in the given expression?
25% of 1280 + (41 × 4) = ?2
Simplify the following expression:
((32)4 - 1)/33×31× (210+1)
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