Question
A milkman initially prepared a mixture of milk and water
in the ratio of 11:3. Later, he replaced half of the mixture with 30 liters of water, resulting in a new mixture where the milk content became 55%. Determine the original total quantity of the mixture.Solution
Let the original quantity of milk and water in the mixture be '11x' litres and '3x' litres, respectively After replacing half the mixture with 30 litres of water, Quantity of milk remaining in the mixture = 11x ÷ 2 = '5.5x' litres Quantity of water remaining in the mixture = 3x ÷ 2 + 30 = (1.5x + 30) litres According to the question, 5.5x/(1.5x + 30 + 5.5x) = 55/100 Or, 550x = 385x + 1650 So, 165x = 1650 So, x = 1650 ÷ 165 = 10 So, original quantity of the mixture = 11x + 3x = 14x = 14 X 10 = 140 litres
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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