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      Question

      Two trains β€˜T5’ and β€˜U5’ of lengths 800 metres

      and 400 metres respectively are travelling towards each other. Ratio of speed of β€˜T5’ to β€˜U5’ is 5:3. If the trains take 60 seconds to cross each other from the time they meet, then find the average of speeds (in km/h) of trains β€˜T5’ and β€˜U5’.
      A 18 km/h Correct Answer Incorrect Answer
      B 21 km/h Correct Answer Incorrect Answer
      C 24 km/h Correct Answer Incorrect Answer
      D 36 km/h Correct Answer Incorrect Answer
      E 45 km/h Correct Answer Incorrect Answer

      Solution

      Let the speeds be 5y and 3y m/s respectively.
      Relative speed = 5y + 3y = 8y m/s
      ATQ,
      8y Γ— 60 = 800 + 400
      β‡’ 480y = 1200
      β‡’ y = 2.5
      Therefore, required average = (5y + 3y) Γ· 2 = 4y
      = 4 Γ— 2.5 = 10 m/s = 10 Γ— (18/5) = 36 km/h

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