Question
Two trains ‘T1’ and ‘U1’ of lengths 540 metres and 360 metres respectively are travelling towards each other. Ratio of speed of ‘T1’ to ‘U1’ is 3:2. If the trains take 45 seconds to cross each other from the time they meet, then find the average of speeds (in km/h) of trains ‘T1’ and ‘U1’.
Solution
Let the speed of ‘T1’ and ‘U1’ be ‘3y’ and ‘2y’ m/s respectively.
Relative speed = 3y + 2y = 5y m/s
ATQ,
5y × 45 = 540 + 360
⇒ 225y = 900
⇒ y = 4
Therefore, required average = (3y + 2y) ÷ 2 = 2.5y
= 2.5 × 4 = 10.0 m/s = 10.0 × (18/5) = 36 km/h
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