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    Question

    The average of 5 numbers is 42.

    When one of the numbers is excluded, the average of the remaining four numbers becomes 38. Determine the value of the number that was excluded?
    A 75 Correct Answer Incorrect Answer
    B 65 Correct Answer Incorrect Answer
    C 58 Correct Answer Incorrect Answer
    D 50 Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let the excluded number be 'a' So, 42 × 5 = 38 × 4 + a Or, 210 = 152 + a Or, a = 58

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