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      Question

      The average of 5 numbers is 42.

      When one of the numbers is excluded, the average of the remaining four numbers becomes 38. Determine the value of the number that was excluded?
      A 75 Correct Answer Incorrect Answer
      B 65 Correct Answer Incorrect Answer
      C 58 Correct Answer Incorrect Answer
      D 50 Correct Answer Incorrect Answer

      Solution

      ATQ,

      Let the excluded number be 'a' So, 42 ├Ч 5 = 38 ├Ч 4 + a Or, 210 = 152 + a Or, a = 58

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