Question
The average of 5 numbers is 42.
When one of the numbers is excluded, the average of the remaining four numbers becomes 38. Determine the value of the number that was excluded?Solution
ATQ,
Let the excluded number be 'a' So, 42 Γ 5 = 38 Γ 4 + a Or, 210 = 152 + a Or, a = 58
((67)32 × (67)-18 / ? = (67)βΈ
What will come in the place of question mark (?) in the given expression?
?% of (112 X 3 + 164) + 75 = 2 X 140 + 35
20% of 450 - 15% of 400 = 25% of ?
β121 + β961β β289 =?2
45% of 1020 + ?% of 960 = 747

(γ(0.4)γ^(1/3)Β Γ γ(1/64)γ^(1/4)Β Γ γ16γ^(1/6)Β Γ γ(0.256)γ^(2/3))/(γ(0.16)γ^(2/3)Β Γ 4^(-1/2)Β Γγ1024γ^(-1/4) ) = ?
(512) (2/3) Γ β64 Γ· (512) (1/3) = (64) (?/2) Γ· (2)6Β
1231 + 1312 + 2113 β 3211 = ?
Simplify the following expression:-