Question
A train travelling at a speed of 80 km/h, takes 27
seconds to cross a pole. If the train increased its speed by 10 km/h, how long would it take to cross a 150-metre-long platform?Solution
80 km/h = 80 X (5/18) = (200/9) m/s So, length of the train = (200/9) X 27 = 600 metres Increased speed of the train = 80 + 10 = 90 km/h = 90 X (5/18) = 25 m/s So, time taken to cross a 150-metre-long platform = (600 + 150) ÷ 25 = 30 seconds
Which of the following interchange of sign would make the given equation correct?
45 × 9 + 5 ÷ 4 = 25
Which two signs need to be interchanged to make the following equation correct?
75 – 18 × 80 ÷ 16 + 40 = 125
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