Question
The greatest number of four digits which when divided by
5, 8, 11 leave remainders 2, 4, 6 respectively is:Solution
The difference between divisor and the corresponding remainder is equal (i.e 3). LCM of 5, 8 and 11 = 440 Largest 4-digit number = 9999 After dividing 9999 by 440 we will get the remainder as 319. Therefore, the number divisible by 440 = 9999 – 319 = 9680 If 3 is subtracted from the number 9680 the resulting number will follow the condition in the question and that number is 9677.
? = (597.98 ÷ (6.97 2.01 – 3.1)) × 12.9
1153, 1206, ?, 1326, 1393, 1464
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