Question
In the questions, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.
In the questions, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the correct option.
I. x² + 240 = 31x
II. (y - 20)(y - 16) = 0
More Quadratic equation Questions
- I. (2x-3)3+ 1/((2x-3)³)=2 II. 4y²+(y+8)^2= 157
- I. 66x² - 49x + 9 = 0 II. 46y² - 37y - 30 = 0
- I. p2 – 2p – 15 = 0 II. q2 + 4q – 12 = 0
- If the roots of the quadratic equation 5x² + 4x + 6 = 0 are α and β, then what is the value of [(1/α) + (1/β)]?
- Quantity I: The cash price of a notebook is Rs. 100 but is can also be purchased on 11 monthly equal instalments of Rs. 10 each. Find rate of S.I.? Quantit...
- I. 2x2 + 13x + 21 = 0 II. 3y2 + 34y + 63 = 0
- Solve the quadratic equations and determine the relation between x and y: Equation 1: 27x² - 114x + 99 = 0 Equation 2: 18y² - 70y + 68 = 0
- I. 2(x+2)+ 2(-x)=5 II. (1/(y+1)+ 1/(y+5))=(1/(y+2)+ 1/(y+4))
- For what values of k does the equation x² – (k+1)x + k = 0 have two distinct real roots, both greater than 1?
- I. 27x² + 120x + 77 = 0 II. 56y² + 117y + 36 = 0
Relevant for Exams:
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
